Agurus - Wed Nov 08, 2006 9:20 pm
Post subject:
Pardon my handwriting, but here is my work any thing you guy see wrong?
Cyan~Fire - Thu Nov 09, 2006 12:39 am
Post subject:
Working on a response, I'll edit in a few minutes...
Edit: OK, here's what I have to say. I'm tired right now and I need to get up early tomorrow (... for Physics) so I'll check it in the morning and I'll actually try to solve the problem.
Agurus - Thu Nov 09, 2006 8:34 am
Post subject:
Fr= Force Reaction, same as Fn basically.
2w= weight of bar
w= weight of ball (go weights from problem)
Cyan~Fire - Thu Nov 09, 2006 12:27 pm
Post subject:
OK, well you're right, it is the normal force. I guess you can call it whatever you want when you're doing your own work, but it would probably be good to call it the normal force when showing your work to others (such as us or your teacher).
So... everything else I said still stands. I realize that w is the weight of the ball (and the bar, reread the problem). So why did you multiply the coefficient of friction by the weight to get the frictional force? Why is the normal force even in (what I'm assuming is) your torque equation?
Finally, you didn't answer my question. What did you pick for your axis?
Quan Chi2 - Fri Nov 10, 2006 4:41 pm
Post subject:
I wish I knew how to add.